Question

The length of a rectangle is three times its width.

If the perimeter of the rectangle is 48 in, find its length and width.
length: in
width: in

Answer 1

Length: 18 in.

Width: 6 in.

We can use “x” as the width in this scenario. If the width is x, then the length is 3x, since length is three times the width. The perimeter would be length + length + width + width. Since the perimeter is 48, we could say that:

x + x + 3x + 3x = 48

Which simplifies to 8x=48

If you divide by 8 on both sides, you get

X=6. Then you Can plug 6 back into your x width and 3x length.

(See attached image) hope this helped!

Answer 2

Hello!

Let's set up some variables:

• L: length of the rectangle
• W: width of the rectangle

Let's consider the relationship between the length and the width:

• The length of a rectangle is three times its width

`\hookrightarrow L=3W`

The perimeter of the rectangle is equal to 48 and 2W + 2L

`\hookrightarrow 2L + 2W = 48`

Let's replace the 'L' in terms of 'W' and solve:

`2(3W) + 2W = 48\\6W + 2W=48\\8W = 48\\W = 6`

Since L = 3W

`\hookrightarrow L = 3W = 3*6 = 18`

Answer:

• Length = 18
• Width = 6

Hope that helps!