Question

Find the area of the triangle if A=1/2bh

Answer 1

Here the base is 12x - 4 and the height is 3x + 2, so let's plug these into the formula:


`\sf A=(1)/(2)bh`


`\sf A=(1)/(2)(12x-4)(3x+2)`

First distribute 1/2 into the first parenthesis, we do this by multiplying it to every term:


`\sf(1)/(2)\cdot 12x=6x`

`\sf(1)/(2)\cdot -4=-2`

So we have:


`\sf (6x-2)(3x+2)`

Distribute, multiply every term in the first parenthesis to every term in the second:


`\sf 6x\cdot 3x=18x^2`

`\sf 6x\cdot 2=12x`

`\sf -2\cdot 3x=-6x`

`\sf -2\cdot 2=-4`

So we're left with:


`\sf 18x^2+12x-6x-4`

Combine like terms(12x - 6x = 6x):


`\boxed{\sf 18x^2+6x-4}`

Answer 2

A= 12x-4(3x+2)/2. 36x2+24x-12x-8. 36x2+12x-8/2. 18x2+6x-4.