Question

A compound is found to contain 26.96 % sulfur , 13.45 % oxygen , and 59.59 % chlorine by mass.

Answer 1

If the compound is 100g
then 25.96g sulfur , 13.45g oxyegn and 59.59g chlorine.
sulfur: 25.96g/32.065g/mole=0.809moles
oxygen: 13.45g/16.0g/mole=0.84moles
chlorine: 59.59g/35.45g/mole=1.63moles
1.63:0.81:0.84
is almost
2:1:1
therefore, we can say it is
SOCl2

Answer 2

S₄O₁Cl₈

Step-by-step explanation:

Given,

Mass of S = 26.96 g

Mass of O = 13.45 g

Mass of Cl = 59.59 g

Atomic mass of S = 32.065 u

Atomic mass of O = 15.999 u

Atomic mass of Cl = 35.453 u

Moles of S =
`(26.96 g)/(32.065 u)` = 0.84

Moles of O =
`(3.45 g)/(15.999 u)` = 0.2156

Moles of Cl =
`(59.59 g)/(35.453 u)` = 1.68

Dividing by the smallest mole to get molar ratio:

`(0.84)/(0.2156)`,
`(0.2156)/(0.2156)`,
`(1.68)/(0.2156)`

3.89, 1, 7.79

~ 4, 1, 8

The empirical formula is S₄O₁Cl₈