Answer:
Given inequality,

Using the property a > b ⇒ a + c > b + c ∀ a, b, c ∈ R

Using the property a > b ⇒ a - c > b - c ∀ a, b, c ∈ R



Case 1 : If x > 0 ⇒ -x < 0
∵ a > b ⇒ ca < cb if c < 0,

Now, -1/2 < 0

Case 2 : If x < 0 ⇒ -x > 0
∵ a > b ⇒ ca > cb if c > 0,

Now, -1/2 < 0
