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The time it takes a spinner to stop completely is 12 seconds. If the spinner completes 6 revolutions in this time, what was the average angular velocity of the spinner, in radians per second, for the 12-second interval?

User Rjmoggach
by
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2 Answers

4 votes

Answer:

3.14 rad/s is the average angular velocity of the spinner.

Explanation:

Average angular velocity :


\omega=(\Delta \theta )/(\Delta t)

Change in angular displacement Δθ= 6 revolutions

1 revolution = 360°

6 revolutions = 6 × 360° = 2160° = 37.70 rad

(1°= 0.0174533 radians )

Change in time Δt= 12 s

Average angular velocity of the spinner =


=(37.70 rad)/(12 s)=3.14 rad/s

3.14 rad/s is the average angular velocity of the spinner.

User Duane Moore
by
8.6k points
6 votes
The angular velocity by definition is given by:
w = rev / t
Where:
rev: revolutions
t: time
Substituting values we have:
w = (6 * (2 * pi)) / (12)
w = 3.141592654 rad / s
Answer:
the average angular velocity of the spinner, in radians per second, for the 12-second interval is:
w = 3.141592654 rad / s
User Misinglink
by
8.1k points

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