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36 votes
36 votes
Decay (calculus problem)

Decay (calculus problem)-example-1
User Rafaelfranca
by
3.2k points

1 Answer

23 votes
23 votes

Answer:

Explanation:

If the half-life is k days, then you have

(1/2)^(300/k) = 0.696

k = 573.788

makes sense, since 69.6% is greater than 50%

Now solve for t in

(1/2)^(t/573.788) = 1/3

t = 909.432 days

makes sense -- about 1.5 half-lives

User Joanne Demmler
by
3.0k points
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