Question

which of the following gives an equation of a line that passes through the point (6 over 5, -19 over 5) and is parallel to the line that passes through th organ point (-2,-12)

Answer 1

c

Explanation:

egde said it was right'

Answer 2

One equation for this would be


`y = (41)/(16) x-(55)/(8)`

We start by finding the slope between the two points:


`m=(y_2-y_1)/(x_2-x_1)=(-12-(-19)/(5))/(-2-(6)/(5)) \\ \\=(-12+(19)/(5)) / (-2-(6)/(5)) \\ \\=((-60)/(5)+(19)/(5)) / ((-10)/(5)-(6)/(5)) \\ \\=(-41)/(5) / (-16)/(5)=(-41)/(5) * (-5)/(16)=(41)/(16)`

A line parallel to this one will have the same slope. We will use point-slope form to write our equation:


`y-y_1=m(x-x_1) \\ \\y-(-19)/(5)=(41)/(16)(x-(6)/(5)) \\ \\y+(19)/(5)=(41)/(16)x- (41)/(16) * (6)/(5) \\ \\y+(19)/(5)=(41)/(16)x-(246)/(80) \\ \\y+(304)/(80)=(41)/(16)x-(246)/(80) \\ \\y=(41)/(16)x-(246)/(80)-(304)/(80) \\ \\y=(41)/(16)x-(550)/(80) \\ \\y=(41)/(16)x-(55)/(8)`