Question

HELPPPPPPPPPPPPPP PLZZZZZZZZZZZZZZZZ

Answer 1

First Term = a₀

--------------------------------------------------------------------
Second term is 3 greater than 1/2 of First Term:
--------------------------------------------------------------------


`\text {Second Term = } (1)/(2) a_0 + 3`


`\text {Second Term = } (a_0 + 6)/(2)`

--------------------------------------------------------------------
Third term is 3 greater than 1/2 of Second Term:
--------------------------------------------------------------------


`\text {Third Term = } (1)/(2) (\ (a_0 + 6)/(2) ) + 3`


`\text {Third Term = } \ (a_0 + 6)/(4) + 3`


`\text {Third Term = } \ (a_0 + 6 + 12)/(4)`


`\text {Third Term = } \ (a_0 + 18)/(4)`

--------------------------------------------------------------------
Ratio of the third term to the second term:
--------------------------------------------------------------------


`(a_0 + 18)/(4) : (a_0 + 6)/(2)`


`(a_0 + 18)/(4) : (2a_0 + 12)/(4)`


`a_0 + 18 : 2a_0 + 12`

--------------------------------------------------------------------
Put in in fraction form:
--------------------------------------------------------------------


`(a_0 + 18 )/(2a_0 + 12)`

--------------------------------------------------------------------
Answer: D
--------------------------------------------------------------------

Answer 2

a₁ = (a₀/2) +3 = (a₀ +6)/2
a₂ = (a₁/2) +3 = (a₀/2 +3)/2 +3
= (a₀ +18)/4

Then a₂/a₁ is
a₂/a₁ = ((a₀ +18)/4)/((a₀ +6)/2)
= (a₀ +18)/(2a₀ +12) . . . . . . . . matches selection D