Question

Eric randomly surveyed 150 adults from a certain city and asked which team in a contest they were rooting​ for, either north high school or south high school. from the results of his​ survey, eric obtained a​ 95% confidence interval of​ (0.52,0.68) for the proportion of all adults in the city rooting for north high. what proportion of the 150 adults in the survey said they were rooting for north high​ school?

Answer 1

0.60

Step-by-step explanation:

Please see attachment

Answer 2

Interval at 95% confidence = p+/- Z sqrt (p(1-p)/n)
Upper interval => 0.68=p+1.96 sqrt (p(1-p)/n)
Lower interval => 0.52=p-1.96 sqrt (p(1-p)/n)
Putting sqrt term to be "q"

0.68=p+1.96q
0.52=p-1.96q

Adding the two equations to solve for p (proportion of 150 adults rootng for North high school);
1.2 = 2p => p=0.6