Question

Using equation e=(hcrh)(1n2)=(−2.18×10−18j)(1n2), calculate the energy of an electron in the hydrogen atom when n= 5.

Answer 1

8.72 x 10^(-20)J

Hope this helps!! ( If not sorry!)

Answer 2

The given formula for energy is:

`E = hcR_(H)((1)/(n^(2)))` (1)

where,

h = planck's constant

c =
`(1)/(\lambda )` =
`\\u` (frequency)

n = energy level

Substitute the given value of n and
`hcR_(H)` in formula (1)

`Energy = (-2.18 * 10^(-18 )J)* ((1)/(5^(2)))`

=
`(-2.18 * 10^(-18 )J)* ((1)/(25))`

=
`(-2.18 * 10^(-18 )J)* (0.04)`

=
`-0.0872 * 10^(-18 )J`

=
`-8.72 * 10^(-20 )J`

Thus, energy of an electron in the hydrogen atom when n = 5 is
`-8.72 * 10^(-20 )J`