Question

Find z such that 87.9% of the standard normal curve lies to the left of z. (round your answer to two decimal places.) z =

Answer 1

Answer with explanation:

It is given that, 87.9% of the standard normal curve lies to the left of z.

Z (87.9%)

`=(87.9)/(100)\\\\=0.879`

Total Area under Z curve =1

Now, we have to find area left of, (Z value =87.9%=88%)=0.88

`Z_(0.88)=0.8106`

⇒Area to left of Z curve , when, (Z value =87.9%=88%)=0.88

= 0.81 (Approximation to two decimal Places)

Answer 2

From standard normal distribution tables and with area to the left of Z being 87.9% or 0.879,

Z= 1.17 (that is, 1.1 at the left column + 0.07 at the top row where 0.879 is found)