Question

Consider the combustion of liquid methanol, ch3oh(l): ch3oh(l)+3/2o2(g)→co2(g)+2h2o(l)δh=−726.5kj part a what is the enthalpy change for the reverse reaction?

Answer 1

The enthalpy change for the reverse reaction can be determined by flipping the sign of the initial enthalpy change for the forward reaction. In this case, the enthalpy change for the combustion of liquid methanol is -726.5 kJ, so the enthalpy change for the reverse reaction is +726.5 kJ.

Step-by-step explanation:

The enthalpy change for the reverse reaction can be determined by simply flipping the sign of the initial enthalpy change for the forward reaction. In this case, the enthalpy change for the combustion of liquid methanol is -726.5 kJ. Therefore, the enthalpy change for the reverse reaction is +726.5 kJ.

Answer 2

For any reaction the enthalpy change in the forward direction and enthalpy change in reverse direction is equal in magnitude and opposite in sign .  if the enthaly change in forward direction is ( -726.5 kj )   then enthalpy change in the reverse direction must be ( +726.5 Kj)