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7 votes
7 votes
Helppp

7 √(?) = 55
Plsss

(5)/(10) = what


User Sabrams
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2 Answers

23 votes
23 votes

Answer:

The first questions unknown equals


(3025)/(49)

The second question is unclear. I assume it is to simplify if that is the case the answer will be.


(1)/(2)

Explanation:

First Question I made ?=x for simplicity.


7 √(x) = 55

then I divide both sides by 7


√(x) = (55)/(7)

then I square both sides


x = (3025)/(49)

Question 2

I simplified by dividing both the denominator and the numerator by their HCF (highest common factor) which is 5


(5 / 5)/(10 / 5)

which equals


(1)/(2)

19 votes
19 votes

Answer:


\textsf{1.} \quad 7\sqrt{(3025)/(49)}=55


\textsf{2.} \quad (5)/(10)=(1)/(2)

Explanation:

Question 1

Let x be the unknown number:


\implies 7√(x)=55

Divide both sides of the equation by 7:


\implies (7 √(x))/(7)=(55)/(7)


\implies √(x)=(55)/(7)

Square both sides of the equation:


\implies \left(√(x)\right)^2=\left((55)/(7)\right)^2


\implies x=(55^2)/(7^2)


\implies x=(3025)/(49)

Question 2

Divide the numerator and the denominator by the highest common factor:


\implies (5 / 5)/(10 / 5)=(1)/(2)

User U W
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