Question

F(x)=y^5-2y^3+y find the zeros of this function​

Answer 1

Answer: y=0 y=-1 y=1

Explanation:

`\displaystyle\\f(y)=y^5-2y^2+y\\\\y^5-2y^2+y=0\\\\y(y^4+2y^2+1)=0\\\\y((y^2)^2+2(y^2)(1)+1^2)=0\\\\y(y^2-1)^2=0\\\\y=0\\\\(y^2-1)^2=0\\\\y^2-1-0\\\\(y+1)(y-1)=0\\\\y+1=0\\\\y+1-1=0-1\\\\y=-1\\\\y-1=0\\\\y-1+1=0+1\\\\y=1`