Question

The length of a rectangle is four times its width. if the perimeter of the rectangle is 80yd, find its length and width.

Answer 1

lets assume Width=x and Length=Y
y=4x

P= 2(x+y)
80=2(x+4x)
80/2= 5x
40= 5x
x= 8

Answer 2

The length is 8. the width is 32.

32(2) = 64

8(2) = 16

64+16 = 80

So the length would be 8 and the width would be 32 since it's 4 times the length.

Hope this helped!