Question

If it takes 254 ml of 0.32 m naoh to neutralize 425 ml of an hcl solution, what is the concentration of the hcl?

Answer 1

To determine the concentration of the HCl solution, calculate the moles of NaOH used, then use the 1:1 molar ratio between HCl and NaOH to find that the concentration of HCl is approximately 0.1912 M.

Step-by-step explanation:

The question is regarding the calculation of the concentration of an HCl solution using a titration method with NaOH. When 254 ml of 0.32 M NaOH is used to neutralize 425 ml of an HCl solution, we can find the concentration of HCl by using the concept that the number of moles of HCl will equal the number of moles of NaOH at the equivalence point, since the reaction between NaOH and HCl proceeds in a 1:1 molar ratio (HCl + NaOH → NaCl + H2O).

First, calculate the moles of NaOH: moles NaOH = volume (L) × concentration (M) = 0.254 L × 0.32 M = 0.08128 moles.

Since the molar ratio of NaOH to HCl is 1:1, the moles of HCl will also be 0.08128. Then, we can calculate the concentration of HCl: concentration HCl = moles/volume = 0.08128 moles / 0.425 L = 0.1912 M.

Answer 2

You are titrating an acid into a base to determine the concentration of the base. The endpoint of the neutralization is reached but the stopcock on the buret sticks slightly and allows a few more