Question

A car with a mass of 1500 kg travelling at 5m / s is accelerated for 10.0 s to a speed of 25m / s What force was required? The coefficient of rolling kinetic friction was 0.009.

Answer 1

Force:

F = 3130 N

Step-by-step explanation:

Given:

m = 1500 kg

V₀ = 5 m/s

V = 25 m/s

Δt = 10.0 s

μ = 0.009

g = 9.8 m/s²

___________

F - ?

1)

Car acceleration:

a = (V - V₀) / Δt = (25 - 5) / 10.0 = 2 m/s²

2)

Friction force:

F₁ = μ*m*g

3)

According to Newton's second law:

m*a = F - F₁

Force:

F = m*a + F₁

F = m*a + μ*m*g

F = m*( a + μ*g) = 1500*(2 + 0.009*9.8) ≈ 3130 N