Question

If a net force of 25 N is exerted over a distance of 4 m to the right on a 2 kg mass initially at rest and moves it, what is the final velocity of the object? v = _____ m/s

Answer 1

Answer: 10 m/s

Given:

Force, F = 25 N

Initial velocity
`u=0 m/s^(2)`

Distance moved, s= 4 m

mass, m = 2 kg

Formula Used:

`F = ma`

where a is the acceleration.

equation of motion:

`2as=v^(2)-u^(2)`

First, we would calculate the acceleration from the formula for force.

`a= (F)/(m)=(25)/(2)m/s^(2)`

Using the equation of motion, we can find the final velocity now:

`2`×
`(25)/(2)`×
`4= v^(2)-0^(2)`

taking the square root on both sides and ignoring the negative sign:

v= 10 m/s