29.3k views
0 votes
Determine the end behavior for function ƒ(x) = (x2 + 1)2 (2x – 3)

User Lym Zoy
by
8.1k points

2 Answers

5 votes

Answer:


\lim_(x \to \infty) x^(5) = \infty


\lim_(x \to -\infty) x^(5) = -\infty

Explanation:

We have the following function:


f(x) = (x^(2)+1)^(2)*(2x - 3)

It is a fifth order polynomial. The end behavior of a function of x is the limit as x goes to infinity. So only the
x^(5) term is important.

So:


\lim_(x \to \infty) x^(5) = \infty


\lim_(x \to -\infty) x^(5) = -\infty

User Ortund
by
8.8k points
7 votes
It's an odd-degree polynomial with a positive x^5 coefficient. The general shape is "/".

It goes to -∞ for large negative x.
It goes to +∞ for large positive x.
Determine the end behavior for function ƒ(x) = (x2 + 1)2 (2x – 3)-example-1
User Md Alamin
by
8.4k points