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The center of a circle is at (-3, 1) and it’s radius is 9.

What is the equation of the circle?

(x - 3)^2 + (y + 1)^2 =81

(x - 3)^2 + (y + 1)^2 = 18

(x + 3)^2 + (y - 1)^2 =81

(x + 3)^2 + (y - 1)^2 =18

User Oji
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1 Answer

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Greetings!

Answer:

(x + 3)² + ( y - 1)² = 81

Explanation:

To go in reverse, you need to remember that in the equation:

(x - a)² + (y - b)² = r²

a is the x coordinate of the centre and b is the y coordinate of the centre.

As -3 is the x coordinate, we can replace a with 3, and then replace b with 1:

(x - -3)² + (y - 1)² = r²

The two negatives change to a positive:

(x + 3)² + ( y - 1)² = r²

If r is already given as 9, r² is simply 9²

(x + 3)² + ( y - 1)² = 9²

(x + 3)² + ( y - 1)² = 81

So the equation of the circle is (x + 3)² + ( y - 1)² = 81


Hope this helps!



User Tintin
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