Answer:
b. sin (a +b) = sin a cos b + cos a sin b
Explanation:
Since you're trying to prove a relation involving the sine of a sum, that is the identity you would use:
sin (a +b) = sin a cos b + cos a sin b
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sin(90° +q) = sin(90°)cos(q) +cos(90°)sin(q)
= 1·cos(q) +0·sin(q)
= cos(q)