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What is the sum of the first 10 terms of the sequence defined by an=3n-3?

User RyPope
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2 Answers

4 votes
The answer is D. 135
User Irmen De Jong
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Answer:

The sum of first 10 terms of the sequence defined by
a_n=3n-3 is 135.

Explanation:

Given : nth term of a sequence as
a_n=3n-3

We have to find the sum of first 10 terms of the sequence.

Consider the nth term of a sequence as
a_n=3n-3

Then put n = 1 to get the first term


a_1=3(1)-3=0

put n = 2 to get the next term


a_2=3(2)-3=6-3=3

put n = 3 to get the next term


a_3=3(3)-3=9-3=6

put n = 4 to get the next term


a_4=3(4)-3=12-3=9

Thus, the sequence is of the form 0, 3, 6, 9,.....

Thus, the above is an arithmetic sequence with a = 0 and common difference (d) = 3

Thus, Sum of 10 terms is given by


S_n=(n)/(2)(2a+(n-1)d)

n = 10 , a = 0 , d = 3

Put we get,


S_(10)=(10)/(2)(2(0)+(10-1)3)

Simplify, we have,


S_(10)=5(9* 3)


S_(10)=135

Thus, the sum of first 10 terms of the sequence defined by
a_n=3n-3 is 135.

User Chely
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