Question

The sum of the squares of two consecutive even integers is 100. find the two integers?

Answer 1

x = smaller number

x^2+(x+2)^2=100
x^2+x^2+4x+4=100
2x^2+4x-96=0
x^2+2x-48=0
(x+8)(x-6)=0
x=-8,6

Must be positive. So, 6 and 8.