let the load car = y , and Andy will take time x (min.) to load the car
So,
The rate of Andy to load the car = y/x
And we given that: Dennis load the car in 28 min.
So,
The rate of Dennis to load the car = y/28
If both are loading the car in time = t = 21 min
then:
y = (y/x) t + (y/28) t ⇒ divide all equation by y and substitute with t
∴ 1 = (21/x) + (21/28) ⇒ multiply all equation by 28x
28x = 21*28 + 21x
28x - 21 x = 588
7x = 588
∴ x = 84 min.
Which mean Andy will take 84 min. to load the car alone.