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SHOW STEPS PLEASE!!!

SHOW STEPS PLEASE!!!-example-1
User Arbales
by
5.9k points

1 Answer

2 votes
tanθ + cotθ = 1/sinθcosθ

since we know that;

tanθ = sinθ/cosθ, and

cot
θ = cosθ/sinθ

now when we add tan
θ and cotθ and replace their values;

tan
θ + cotθ=sinθ/cosθ + cosθ/sinθ

For a common denominator to add those two fractions, the obvious choice is sinθ.cosθ , so

tanθ + cotθ = sin²θ/sinθcosθ + cos²θ/sinθcosθ =sin²θ + cos²θ / sinθcosθ

now we can use the identity that;

sin²θ + cos²θ = 1

So,

tanθ + cotθ = 1/sinθcosθ

User Wizche
by
6.7k points
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