Question

Solve by completing the square 9x^ - 18 x +93= -6

Answer 1

`9x^2 - 18 x + 93= -6`

take away 93 from both sides

`9x^2 - 18 x = - 99`

Divide by 9 through

`x^2 - 2 x = - 11`

Add (b/2)^2 to form perfect square

`x^2 - 2 x + ( (2)/(2) )^2 = - 11 + ( (2)/(2) )^2`

Form perfect square

`(x - 1)^2 = - 10`

Square root both sides to find x

`x - 1 = \pm √(-10)`

add 1 on both sides

`x = 1+ i√(10) \ or \ 1- i√(10)`