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Determine the tension in the cable and the horizontal and vertical components of reaction of the pin

a. the pulley at d is frictionless and the cylinder weighs 80 lb . (

User Merri
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Since the pulley does not have friction, the two segments of the cable are subject to the same tension force T. Based on the free-body diagram shown above, we have


EM _(A) = 0 {\to T x 5 + (2)/( √(5) ) T x 10 - W x 13 = 0

Thus, we get


T = (13W)/((5 + 20/ √(5)) ) = (13 x 80)/((5 + 20/ √(5))) = 74.583 (Ib)

To find the horizontal support force, we have


EF_(X) = 0 \to A_(X) - (1)/( √(5) ) T = 0

Thus,


A_(X) = (1)/( √(5) ) T = (1)/( √(5) ) x 74.583 = 33.354 (Ib)
User Trevor Allred
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