Question

Which equation results from applying the secant and tangent segment theorem to the figure?

12(a + 12) = 10^2
10 + 12 = a^2
10(a + 10) = 12^2
10(12) = a^2

Answer 1

C) 10(a+10)=12²

Explanation:

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Answer 2

1. You must apply the Secant and Tangent segment theorem, which establishes:

Tangent²=(The whole secant segment)(External secant segment)

2. The whole secant segment is: AD=a+12

3. The external secant segment is: BD=10

4. The tangent segment is: DE=12

5. Then, you have:

DE²=ADxBD
12²=(a+10)10
10(a+10)=12²

6. Therefore, the answer is the third option: 10(a+10)=12²