Question

Jacob has a piece of toast that has butter on one side, and he dropped it twice. Both times, it landed with the butter side up. If he drops it 2 more times, what is the probability that it will have landed butter side up a total of 3 times?

Answer 1

The answer should be 50% if im not mistaken

Answer 2

We have been given that Jacob has a piece of toast that has butter on one side, and he dropped it twice and both times it landed with the butter side up.

We are asked to find out what is the probability that it will have landed butter side up a total of 3 times if he drops toast two more times.

Since we know that an event is certain to happen has probability equals to one. So the probability of toast landing 2 times butter side up in the first two tries would be 1.

Now we will find out total outcomes of next two drops.

(Up, Up), (Up, Down), (Down, Up), (Down, Down)

We can see out of our total outcomes only two are our favorable outcomes.

`\\ \text{Probability of an event}=\frac{\text{ Number of favorable outcomes }}{\text{Total number of possible outcomes}}`

Probability of getting 3 times butter side up =

`1\cdot (2)/(4)=(1)/(2)=0.5`

Therefore, probability of getting 3 times butter side up is 0.5.