Question

Write the equation that is perpendicular to y=3x-2 and goes through the

point (-6,-3). *
A:y=3x-2
B:y=-1/3x-5
C:y=3x+8
D:y=1/3x-12

Answer 1

B

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 2 ← is in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/(3)` , then

y = -
`(1)/(3)` x + c ← is the partial equation

To find c substitute (- 6, - 3 ) into the partial equation

- 3 = 2 + c ⇒ c = - 3 - 2 = - 5

y = -
`(1)/(3)` x - 5 ← equation of perpendicular line