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In equilateral ΔABC, AD, BE, and CF are medians. If FO = 4, then AE = A) 4 B) 4 3 C) 8 D) 12

User YanivGK
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2 Answers

5 votes

Answer:

Your answer choice would be C) 8.

Explanation:

User Assaf Stone
by
6.3k points
7 votes

Firstly, we need to draw triangle

we know that

O is a centroid

and centroid divides median into 2:1

so,


(CO)/(FO) =(2)/(1)

we have FO=4

so, we can plug it


(CO)/(4) =(2)/(1)


CO=8

now, we can find CF

CF=OC+FO

CF=8+4

CF=12

now, we can see triangle ACF is a right angled triangle

so, we can use pythagoras theorem


x^2=((x)/(2) )^2+12^2

now, we can solve for x


(3x^2)/(4)=144


x^2=192


x=8√(3)

Since, it is equilateral triangle

so,


AC=x=8√(3)

we know that

E is a mid-point

so,


AE=(AC)/(2)

now, we can plug values


AE=(8√(3))/(2)


AE=4√(3)................Answer


In equilateral ΔABC, AD, BE, and CF are medians. If FO = 4, then AE = A) 4 B) 4 3 C-example-1
User Daniel Flint
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6.3k points