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How much Will be left after

45 hours if an isotope has a half life of 15 hours and you have 371 MGS

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\bf \textit{Amount for Exponential Decay using Half-Life}\\\\ A=P\left( (1)/(2) \right)^{(t)/(h)}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\to &371\\ t=\textit{elapsed time}\to &45\\ h=\textit{half-life}\to &15 \end{cases} \\\\\\ A=371\left( (1)/(2) \right)^{(45)/(15)}\implies A=371\left( (1)/(2) \right)^3

and surely you know how much that is.
User Eddard Stark
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