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Solve 2x2 − 12x + 20 = 0. (5 points) 3 ± i 3 ± 2i 1 ± 2i 2 ± 3i

User NDraskovic
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2 Answers

6 votes
The answer is 3+-i



I hope this helps!!!!!!!!
User Loolooii
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4 votes

We are given this equation:


2x^(2) -12x+20=0

Let us use quadratic formula to find its solution.

The quadratic formula for general quadratic equation of the form ax²+bx+c=0 is given by:


x=\frac{-b\pm \sqrt{b^(2)-4ac}}{2a}

Now on comparing our equation with this general form our a, b and c are:

a=2, b=-12 and c=20

Plugging these values in the formula:


x=\frac{-(-12))\pm \sqrt{(-12)^(2)-4(2)(20)}}{2(2))}

On solving we will get,


x=((12))\pm √((144)-(160)))/((4))

Simplifying we will get,


x=((12))\pm √(-16))/((4))

square root of -1 is "i".


x=((12))\pm \-4i)/((4))

taking 4 common out as gcf in numerator,


x=3\pm i

Answer : x=3+i and x=3-i


User Jkupczak
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