Question

Factor completely 6a^3-10a^2+3a-5

Answer 1

`(2a^2+1)(3a-5)`

Explanation:

Since it has 4 terms, the cubic expression can be factored using grouping. Use parenthesis to group terms in two and factor by GCF.

`6a^3-10a^2+3a-5\\(6a^3-10a^2)(3a-5)\\2a^2(3a-5)+1(3a-5)`

Since 3a-5 repeats, the factoring is complete and correct. The factors are then
`(2a^2+1)(3a-5)`.