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How many moles are in 64.92g of AgNO3

2 Answers

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Answer: 0.38

Step-by-step explanation:

User Jason Saruulo
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The formula to find moles is:

n = m / M

m stands for mass, which in this case m = 64.92g

M stands for molar mass. You would need to look at the periodic table for each element of AgNO3 and add them together to get M.

n = 64.92 / 107.9 + 14.01 + 3(16)
= 0.382084...
= 0.38 moles (2 d.p)

Hope this helped!
User Gertjan Assies
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