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A 2 kg block is sitting motionless on a ramp at 24° with the horizontal. What is the force of friction on the block that resists its motion?
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A 2 kg block is sitting motionless on a ramp at 24° with the horizontal. What is the force of friction on the block that resists its motion?

User Eujin
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1 Answer

10 votes

Answer:

7.97 N

Step-by-step explanation:


f = m g sin(\alpha) = 2 * 9.8 * sin(24) = 7.97 N

User Pankaj Parkar
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