Question

Factor trinomial 2x^2+13x+15

Answer 1

Try this option:
1. if D≥0, then trinomial 'ax²+bx+c' can be written in form a(x-x1)(x-x2), where x1 and x2 - roots of ax²+bx+c=0.
2. D=b²-4ac=13²-15*2*4=49, then 2x²+13x+15=2(x+5)(x+1.5)

answer: 2(x+5)(x+1.5).

Answer 2

Answer:(2x+3)(x+5)

Explanation: