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What are the zeros of the quadratic function?

f(x)=2x^2−128

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and

2 Answers

2 votes
6 and -6
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User Tim Groeneveld
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6 votes

Answer:


x={\pm}8

Explanation:

The given quadratic function is:


f(x)=2x^2-128

In order to find the zeros of the quadratic function, we put
f(x)=0.

thus, we have


f(x)=0


2x^2-128=0


2x^2=128


x^2=64


x={\pm}8

Therefore, the values of x are 8 and -8.

User Cowfaboo
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