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What is the equation of a circle that has a diameter with endpoints (3, -2) and (-7, 8)?
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What is the equation of a circle that has a diameter with endpoints (3, -2) and (-7, 8)?

User Kevin Lacquement
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The center is the midpoint of the given diameter,
((3, -2) +(-7, 8))/2 = (-2, 3)

The radius is the distance from that to either end,
√(5^2 +5^2) = 5√2

In standard form, the circle's equation is
(x +2)² +(y -3)² = 50
What is the equation of a circle that has a diameter with endpoints (3, -2) and (-7, 8)?-example-1
User David Siro
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