Question

What is the equation of a line that passes through(-6,2) and has a slope of -1/2

A. y=x/2-2
B.y= -x/2-1
C, y=2x+1
D. y=-2x-1

Answer 1

The answer is B because you just plug in the corresponding numbers into y-mx+b. So you'd start with y=-1/2x+b because you're given the slope. Plug -6 in for x and 2 for y, and go from there!

Answer 2

B.
`y = (-x)/(2) -1`

Explanation:

We are given that the equation of the line passes through the point (-6,2) and has a slope -1/2.

Substituting the given values in the formula for slope, we get,

`m=(y_(2)-y_(1) )/(x_(2)-x_(1))`

i.e.
`(-1)/(2)` =
`(y-2)/(x+6)`

i.e. -x-6 = 2y-4

i.e. 2y = -x-2

i.e.
`y = (-x)/(2) -1`

Hence, the equation of the line is
`y = (-x)/(2) -1`