Question

Find the zeros of the polynomial function.

f(x) = x^2 - 12x + 20
I THINK THE ANSWER IS A 2,10

a. 2, 10

b. - 4, -5

c. -2, -10

d. 4, 5

Answer 1

◆ QUADRATIC EQUATIONS ◆


`given \: equation \: is \: , \\ \\ {x}^(2) - 12x + 20 = 0 \\ \\ using \: quadratic \: formula \: , \\ \\ x = \frac{ - b + \sqrt{ {b}^(2) - 4ac } }{2a} \: \: \: \: = \frac{ - ( - 12) + \sqrt{ { (- 12)}^(2) - 4(1)(20) } }{2(1)} \\ \\ x = \frac{ - b + \sqrt{ {b}^(2) - 4ac } }{2a} \: \: \: \: = \frac{ - ( - 12) - \sqrt{ { (- 12)}^(2) - 4(1)(20) } }{2(1)} \\ \\ x = (12 + 8)/(2) \: \: \: \: \: or \: \: \: \: x = (12 - 8)/(2) \\ \\ x = 10 \: \: \: \: \: or \: \: \: \: \: x = 2 \: \: \: ans.`