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A parallelogram has an area of 42cm^2. What would the area be if the base was one-third as long and the height was twice as long?

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Area of a parallelogram is the product of its base and height.

Let the base be "b" and height be "h". So we can write:

Area = bh = 42 cm²

After the change, base is one-third. So the new length of the base will be: b/3
After the change, height is twice as long. So the new height will be : 2h

Area after the change =
(b)/(3)* 2h= (2)/(3) bh
Using the value of bh from equation above we get:

Area after the change =
(2)/(3) * 42 = 28 cm²

So the area of new parallelogram will be 28 cm²
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