Question

What are the zeros of the function?

f(t)=t^2−13t+36



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Answer 1

Set the function equal to 0 and solve for t.

t = 9, 4

Answer 2

For this case, the first thing you should do is factor the expression correctly.
We have then:
f (t) = t ^ 2-13t + 36
We are looking for two numbers that add -13 and multiply den as results 36:
f (t) = (t-9) * (t-4)
Thus, the zeros of the function are:
t1 = 9
t2 = 4
Answer:
t1 = 9
t2 = 4