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Spin a spinner numbered 1-8 two times, land on two the first time and

land on a factor of 8 the second time

User Dabblernl
by
7.9k points

2 Answers

2 votes

Answer:

Required probability = 1/16

Explanation:

When we spin a spinner numbered 1-8, we find that each spin is independent of the other.

HEnce probability for getting any number from 1 to 8 will be equal to 1/8 and remain the same for each spin.

So Probability on two for the first time and factor of 8 on the second time

=Prob (landing on 2)*Prob (landing on any factor of 8)

P(landing on 2) = 1/8

Factors of 8 are 1,2,4,8

Prob (landing on factor of 8) = 4/8

Hence required prob = 1/8(4/8) =1/16

User Chrisjlee
by
7.7k points
4 votes
The correct probability is 1/16.

Explanation:

There is 1 section marked 8 out of 8 sections. This makes the probability of landing on an 8 1/8.

The factors of 4 on this spinner are 1, 2, 4 and 8. This makes 4 sections out of 8, which makes the probability of landing on a factor of 8 equal 4/8=1/2.

Together, the probability of both events would be 1/8(1/2) = 1/16.
User Rowan Parker
by
8.1k points

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