The perimeter is simple enough, just add all the lengths.
10+5+2+2+2+3+8+7+2+3= 44 inches = Perimeter
Now let's solve the area:
Step 1 let's get the area of the 10-inch square and deduct the missing square and rectangle.
10²=A = 100 in²
Now let's solve the 2-inch square a= 2²= A 4²
Now the rectangle is given l=7 w=2 = A = 14 in²
now subtract 100-4-14= 82 in² is the Area if the Figure
Thus: Area = 82 in² & Perimeter = 44 inches