Question

Factorise x3 -3x2 - x+3

Answer 1

`x^(3) - 3 x^(2) - x +3`

You have to do that first.


`=( x^(3) -3x^2)+(-x+3)`

Then, you have to remove out the factor x^2.


`= x^2(x-3) - (x-3)`

Now, factor out the common factor (x-3).


`=(x-3)(x^2-1)`

And at the end, factor x² -1.


`x^2-1=(x+1)(x-1)`

It gives :
`= (x-3)(x+1)(x-1)`

Hope this helps !

Photon