Answer:
Na2CO3 + 2HC2H3O2 → CO2 + H2O + 2NaC2H3O2
Step-by-step explanation:
Label Each Compound With a VariableLabel each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.aNa2CO3 + bHC2H3O2 = cCO2 + dH2O + fNaC2H3O2Create a System of EquationsCreate an equation for each element (Na, C, O, H) where each term represents the number of atoms of the element in each reactant or product.Na: 2a + 0b = 0c + 0d + 1f
C: 1a + 2b = 1c + 0d + 2f
O: 3a + 2b = 2c + 1d + 2f
H: 0a + 4b = 0c + 2d + 3f
Solve For All VariablesUse substitution, gauss elimination, or a calculator to solve for each variable.
Simplify the result to get the lowest, whole integer values.
a = 1 (Na2CO3)
b = 2 (HC2H3O2)
c = 1 (CO2)
d = 1 (H2O)
f = 2 (NaC2H3O2)
Substitute Coefficients and Verify Result
Na2CO3 + 2HC2H3O2 = CO2 + H2O + 2NaC2H3O2
Reactants Products
Na 2 2 ✔️
C 5 5 ✔️
O 7 7 ✔️
H 8 8 ✔️
Since there is an equal number of each element in the reactants and products of Na2CO3 + 2HC2H3O2 = CO2 + H2O + 2NaC2H3O2, the equation is balanced.