Question

Can someone please help solve this math problem with solution? thank u!

Answer 1

Answer: n+3

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Work Shown:

`(n^2+n-6)/(n-2)\\\\((n+3)(n-2))/(n-2)\\\\n+3`

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Step-by-step explanation:

Often when simplifying, it's a good idea to factor and see what cancels (if anything does cancel).

To factor the numerator, think of two numbers that

• multiply to -6
• add to 1

Through trial and error, you should find the two numbers to be 3 and -2

• 3 times -2 = -6
• 3 plus -2 = 1

So that's how
`n^2+n-6` factors to
`(n+3)(n-2)`.

After this point, the (n-2) terms cancel leaving n+3 behind

We can say
`(n^2+n-6)/(n-2)=n+3 \ \ \text{when } n \\e 2`

The
`n \\e 2` is to avoid a division by zero error.