Question

A flask contains 0.230 mol of liquid bromine, br2. determine the number of bromine molecules present in the flask.

Answer 1

the amount of bromine present in the flask = 0.230 moles
Avagadro's number states the number of units present in a single mole.
Avagadro's number is 6.022 x 10²³ units, these could be atoms in the case of elements or molecules in compounds.
the number of bromine molecules in 1 mol = 6.022 x 10²³ molecules of Br bromine molecules in 0.230 mol = 6.022 x 10²³ molecules/mol x 230 mol

number of bromine molecules in the flask = 1.385 x 10²⁶ Br₂ molecules

Answer 2

There are
`1.38506* 10^(23)` of bromine molecules present in the flask.

Step-by-step explanation:

Moles of liquid bromine in the flask = 0.230 mol

As we know that 1 mole is equal to the Avogadro number.

`1 mol=6.022* 10^(23)` atoms/ molecules

So, number of bromine molecules in 0.230 moles of liquid bromine is:

`=0.230* 6.022* 10^(23)=1.38506* 10^(23) molecules`

There are
`1.38506* 10^(23)` of bromine molecules present in the flask.