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If 36 grams of aluminum react with an excess of oxygen, as shown in the balanced chemical equation below, how many grams of aluminum oxide can be formed? (1 point) 4Al + 3O2yields 2Al2O3 68 grams 24 grams
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If 36 grams of aluminum react with an excess of oxygen, as shown in the balanced chemical equation below, how many grams of aluminum oxide can be formed? (1 point)

4Al + 3O2yields 2Al2O3

68 grams
24 grams
272 grams
18 grams

User Joseph Jaquinta
by
8.1k points

1 Answer

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molar mass of Al = 26.98
molar mass of Al2O3 = 101.96
36 / 26.98 = 1.3343 moles Al
set up a proportion : 1.3343 / 4 = x / 2 (let x = moles of Al2O3)
x = 0.66716 moles of Al2O3
0.66716 * 101.96 = 69.024 g of Al2O3
User John Mcfetridge
by
7.3k points
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